1.5x^2-(20+5x)=800

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Solution for 1.5x^2-(20+5x)=800 equation:



1.5x^2-(20+5x)=800
We move all terms to the left:
1.5x^2-(20+5x)-(800)=0
We add all the numbers together, and all the variables
1.5x^2-(5x+20)-800=0
We get rid of parentheses
1.5x^2-5x-20-800=0
We add all the numbers together, and all the variables
1.5x^2-5x-820=0
a = 1.5; b = -5; c = -820;
Δ = b2-4ac
Δ = -52-4·1.5·(-820)
Δ = 4945
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{4945}}{2*1.5}=\frac{5-\sqrt{4945}}{3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{4945}}{2*1.5}=\frac{5+\sqrt{4945}}{3} $

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